logic problems with solutions set 1
Problem: - If in the code, ALTERED is written as ZOGVIVW, then in the same code, RELATED would be written as?
Solution: - Clearly, each letter of the ALTERED is replaced by the letter which occupies the same position from the other end of the English alphabet, to obtain the code. Thus, A, the first letter of the alphabet, is replaced by Z, the last letter. L, the 12th letter from the beginning of the alphabet, is replaced by O, the 12th letter from the end. T, the 7th letter from the end of the alphabet is replaced by G, the 7th letter from the beginning of the alphabet and so on.
Similarly, in the word RELATED, R will be coded as I, E as V, L as O, A as Z, T as G and D as W. Thus, the code becomes IVOZGVW. (Answer)
Problem: - Pointing to a photograph, a lady tells X, “I am the only daughter of this lady and her son is your maternal uncle.” How the speaker is related to X’s father?
Solution: - Clearly, the speaker’s brother is X’s maternal uncle. So, the speaker is X’s mother or his father’s wife.
Problem: - In a school, there were five teachers. A and B were teaching Hindi and English. C and B were teaching English and Geography. D and A were teaching Mathematics and Hindi. E and B were teaching History and French. Answer the following questions:
1) Who among the teachers was teaching maximum number of subjects?
2) Who among the teachers, teaches Hindi?
3) D, B and A were teaching which subjects?
Solution: - The given information can be analysed as under:
Prob 1
Clearly, B teaches maximum number of subjects, i.e. 5.
Three teachers were teaching Hindi – A, B and D.
D, B and A were teaching Hindi.
Logic Problems with Solutions Set 2
Problem: - A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?
Solution: - The movements of the man are as shown in the figure. (A to B, B to C, C to D, D to E).
Prob2
Clearly, DF = BC = 5 km.
EF = (DE – DF) = (9-5) km = 4km
BF = CD = 2 km
AF = AB + BF = AB + CD = (1 + 2) km = 3 km.
Therefore man’s distance from starting point A
= AE = `sqrt(AF^2 +EF^2)` = `sqrt(3^2 + 4^2)`
= `sqrt25` = 5 km (Answer)
I am planning to write more post on Rational Inequalities and ibps exams 2013. Keep checking my blog.
Problem: - Which of the following diagrams correctly represents the relationship among the classes: Tennis fans, Cricket players, Students?
Prob2
Solution: - Some students can be cricket players. Some cricket players can be tennis fans.
Some students can be tennis fans. So, the given items are partly related to each other. So the correct diagram which represents the relationship between the above is option (A).
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